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Physical electronics devices and ics miscellaneous

Physical Electronics Devices and ICs

  1. In the voltage regulator shown below the power dissipation in the zener diode is—


    1. 1 mV
    2. 1.5 mV
    3. 2 mV
    4. 0.5 mV
Correct Option: D

Since in the given problem RZ is zero. so, in order to calculate the power dissipation across the zener diode. We must calculate the current flowing in zener diode
Where, Vth = Thevenin equivalent voltage
Rth = Thevenin equivalent resistance

Vth =
75
= 50 .
1

75 + 1503

=
50
V > VZ
3

Rth = 150 || 75 =
150 × 75
150 + 75

= 50 kΩ
iZ =
Vth
=
50/3

Rth + RL50 kΩ

= 0.33 mA
Now PZ = VZ. iZ = 15 × 0.33 mA
= 0.5 mW
Hence alternative (D) is the correct choice.



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