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In the voltage regulator circuit shown below. The power rating of zener diode is 400 mW. The value of RL that will establish maximum power in Zener diode is—
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- 5 kΩ
- 2 kΩ
- 10 kΩ
- 8 kΩ
Correct Option: B
| Iz (max) = | = | = 40 mA | VZ | 10 V |
| Iz + IL = | = | = 45 mA | 222 | 222 |
IL (min) = 45 – Iz = 45 – 40 = 5 mA
Now,
| RL = | = | = 2 kΩ | IL (min) | 5 mA |
