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					 Find the least number which when divided by 16, 18 and 20 leaves a remainder 4 in each case, but is completely divisible by 7.
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                        - 2884
- 2256
- 865
- 3332
- None of the above
 
Correct Option: A
LCM of 16, 18 and 20 = 720
∴  Required number = 720k + 4 
Where, k is a natural number to be divisible by  7, (720 k + 4) will be  a  multiple of 7. 
Smallest value of  k = 4
∴    Required number = 720 x 4 + 4 = 2884
 
	