We can say that ,

Putting in above equation , x -	1	= y
	x

∴

x +

= x² +

+ 2 =

x +

+ 4 = y² + 4

x²

So, given equation becomes

⇒ y		y -	3		= 0 ⇒ y = 0 or y =	3
			2			2

∴ x -	1	= 0 ⇒ x -	1	=	3
	x		x		2

⇒ x² - 1 = 0 or 2x² - 3x - 2 = 0
⇒ x = ± 1 or ( 2x + 1 ) ( x - 2 ) = 0
⇒ x = ± 1 or - 1/2 or x = 2.
Thus , option C is correct answer .

	x +	1		²	-	3		x -	1		= 4 is :
		x				2			x