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A is older by 4 years to B at one stage. After 16 years of this stage, A will be thrice his present age and B will be five times his present age. How old would A and B be two years before the initially indicated stage?
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- 8 and 4 years
- 10 and 6 years
- 6 and 2 years
- 12 and 8 years
Correct Option: C
Suppose the ages of A and B are P and Q years respectively.
According to question
Age of A = Age of B + 4 years
⇒ P = Q + 4
After 16 years , Age of A + 16 = 3 x Age of A
⇒ P + 16 = 3P
and Age of B + 16 = 5 x Age of B
⇒ Q + 16 = 5Q
⇒ P = 8 and Q = 4
2 years ago their ages
Age of A = 8 – 2 = 6 years
Age of B = 4 – 2 = 2 years
