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The age of a father 10 years ago was thrice the age his son. Ten years later, the father's age will be twice that of his son. The ratio of their present ages is ?
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- 8 : 5
- 7 : 3
- 5 : 2
- 9 : 5
Correct Option: B
Let son's age 10 years ago be x years.
∴ father's age 10 years ago = 3x years
∵ 3x + 20 = 2(x + 20)
⇒ x = 20
∴ Ratio of their present ages = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3
