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One years ago a father was four times as old as his son. After 6 years his age exceeds than twice of his son's age by 9 years. Ratio of their present ages is ?
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- 13 : 4
- 12 : 5
- 11 : 3
- 9 : 2
Correct Option: C
Let son's age 1 year ago be x years.
⇒ Father's age 1 year ago = 4x years
∵ 4x + 7 = 2(x + 7) + 9
⇒ 2x = 23 - 7
⇒ x = 8
Ratio of father's and son's present ages = (4x + 1) : (x + 1) = 33 : 9 = 11 : 3
