Operators
- Which operator works only with integer variables?
-
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NA
Correct Option: D
both decrement & increment
- What do we need to use when we have multiple subscripts?
-
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NA
Correct Option: B
The reason is that operator[] always takes exactly one parameter, but operator() can take any number of parameters.
- What do we need to do to pointer for overloading the subscript operator?
-
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NA
Correct Option: C
If you have a pointer to an object of some class type that overloads the subscript operator, you have to dereference that pointer in order to free the memory.
- What is the output of this program?
#include <iostream>
using namespace std;
class Example
{
private:
int* K;
int L;
public:
Example (int L);
~Example ();
int& operator [] (int num);
};
int& Example::operator [] (int num)
{
return K[num];
}
Example::Example (int L)
{
K = new int [L];
L = L;
}
Example::~Example ()
{
delete [] K;
}
int main ()
{
Example obj (10);
obj [0] = 15;
obj [1] = 10;
obj [2] = 35;
obj [3] = 30;
for (int num = 0; num < 5; ++ num)
cout << obj [num] <<" ";
return 0;
}
-
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NA
Correct Option: E
In this program, we are printing the array in the reverse order by using subscript operator.
- What is the output of this program?
#include <iostream>
using namespace std;
class Example
{
public:
int p;
Example(int num = 0) : p(num) {};
int& operator[](int num)
{
cout << "Interview " ;
return p;
}
int operator[](int num) const
{
cout << "Mania" ;
return p;
}
};
void foo(const Example& n)
{
int Res = n[2];
}
int main()
{
Example n(7);
n[3] = 8;
int Res = n[2];
foo(n);
return 0;
}
-
View Hint View Answer Discuss in Forum
NA
Correct Option: A
In this program, we overloading the operator[] by using subscript operator.
