Control systems miscellaneous


Control systems miscellaneous

  1. Sinusoidal oscillators are—









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    NA

    Correct Option: B

    NA


  1. Which one of the four signals flow graphs shown in (A), (B), (C) and (D) represents the block diagram shown in given figure?Kindle Edition.











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    On drawing the signal flow graph from the given block diagram, we get
    Hence alternative (A) is the correct answer.


    Correct Option: A

    On drawing the signal flow graph from the given block diagram, we get
    Hence alternative (A) is the correct answer.




  1. In a linear system, an input of 5 sin ωt produces an output of 10 cos ωt. The output corresponding to input 10 cos ωt will be equal to—









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    Given
    it means the system is differentiator with ω = 2
    So with,
    ω = 2
    = – 10. ω sin ωt
    = – 10 × 2. sin ωt
    = – 20 sin ωt,

    Correct Option: D

    Given
    it means the system is differentiator with ω = 2
    So with,
    ω = 2
    = – 10. ω sin ωt
    = – 10 × 2. sin ωt
    = – 20 sin ωt,


  1. NA











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    From figure
    C = GR – CH2
    C (1 + H2) = GR

    C
    =
    G
    R1 + H2
    From figure
    C = GR – CH2
    C (1 + H2) = GR
    C
    =
    G
    R1 + H2


    Correct Option: B

    From figure
    C = GR – CH2
    C (1 + H2) = GR

    C
    =
    G
    R1 + H2




  1. A linear second-order system with the transfer function
    G(s) =
    49
    s2 + 8s + 49

    is initially at rest and is subject to a step input signal. The response of the system will exhibit a peak overshoot of—









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    We know that maximum overshoot is given as
    Mp = e– ξπ/√1 – ξ2

    From given T.F. = G
    49
    s2 + 8s + 49

    C.E. = s2 + 8s + 49
    on comparing this equation with the standard equation
    ωns + ω2n = 0
    2 ξωn and ωn = 7
    or
    ξ =
    8
    =
    8
    = .57
    n2 × 7

    % Mp = e
    -3.14 × (0.57)2
    × 100 = 2%
    1 - (0.57)2

    Correct Option: C

    We know that maximum overshoot is given as
    Mp = e– ξπ/√1 – ξ2

    From given T.F. = G
    49
    s2 + 8s + 49

    C.E. = s2 + 8s + 49
    on comparing this equation with the standard equation
    ωns + ω2n = 0
    2 ξωn and ωn = 7
    or
    ξ =
    8
    =
    8
    = .57
    n2 × 7

    % Mp = e
    -3.14 × (0.57)2
    × 100 = 2%
    1 - (0.57)2