Data Types
- Which of the following is the correct output for the program given below?
#include <stdio.h>
int main ( )
{
double d = 2.25;
printf ("%e", d);
printf ("%f", d);
printf ("%g".d);
printf ("%lf\n", d);
return 0 ;
}
-
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250000e + 000 2.250000 2.25 2.250000
Correct Option: C
printf("%e,", d); Here '%e' specifies the "Scientific Notation" format. So, it prints the 2.25 as 2.250000e+000.
printf("%f,", d); Here '%f' specifies the "Decimal Floating Point" format. So, it prints the 2.25 as 2.250000.
printf("%g,", d); Here '%g' "Use the shorter of %e or %f". So, it prints the 2.25 as 2.25.
printf("%lf,", d); Here '%lf' specifies the "Long Double" format. So, it prints the 2.25 as 2.250000.
- Which of the following is the correct output for the program given below?
#include <stdio.h>
int main ( )
{
float f = 43.20;
printf ("%e", f);
printf ("%f", f);
printf ("%g \n" , f);
return 0 ;
}
-
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4.320000e + 001 43.200001 43.2
Correct Option: A
printf("%e,", d); Here '%e' specifies the "Scientific Notation" format. So, it prints the 43.20 as 43.200000e+000.
printf("%f,", d); Here '%f' specifies the "Decimal Floating Point" format. So, it prints the 43.20 as 43.200001.
printf("%g,", d); Here '%g' "Use the shorter of %e or %f". So, it prints the 43.20 as 43.20.
- Which of the following statements are correct about the program given below?
#include <stdio.h>
int main ()
{
float k = 0.7;
if (k < 0.7)
printf ("C\n");
else
printf ("C++\n");
return 0 ;
}
-
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if(k < 0.7) here k is a float variable and 0.7 is a double constant. The float variable k is less than double constant 0.7. Hence the if condition is satisfied and it prints 'C'
Correct Option: A
if(k < 0.7) here k is a float variable and 0.7 is a double constant. The float variable k is less than double constant 0.7. Hence the if condition is satisfied and it prints 'C'
- Which of the following is the correct output for the program given below?
#include <stdio.h>
#include <math.h>
int main ( )
{
printf ( "%f\n" ,sqrt (49.0));
return 0 ;
}
-
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It prints the square root of 49 in the float format(i.e 7.000000).
Correct Option: C
It prints the square root of 49 in the float format(i.e 7.000000).
- Which of the following is the correct output for the program given below?
#include<stdio.h>
int main ( )
{
float *p;
printf ( "%d\n " , sizeof ( p ) );
return 0 ;
}
-
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2 in 16-bit compiler like TC/TC++, 4 in 32-bit compiler like Visual studio or gcc
Correct Option: A
2 in 16-bit compiler like TC/TC++, 4 in 32-bit compiler like Visual studio or gcc
