Unitary Method
- In a dairy farm, 40 cows eat 40 bags of husk in 40 days. In how many days one cow will eat one bag of husk?
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40 cows eat 40 bags of husk in 40 days.
∴ 1 cows eat 40 bags of husk in 40 x 40 days.
∴ 1 cows eat 1 bags of husk in 40 x 40 / 40 days.Correct Option: B
40 cows eat 40 bags of husk in 40 days.
∴ 1 cows eat 40 bags of husk in 40 x 40 days.
∴ 1 cows eat 1 bags of husk in 40 x 40 / 40 days.
∴ 1 cows eat 1 bags of husk in 40 days.
- If the cost of x meters of wire is ‘d’ rupees, that find the cost (in Rupees) of ‘y’ meters of wire at the same rate.
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Cost of x meters ropes = Rs. d
∴ Cost of 1 meters ropes = Rs. d /xCorrect Option: A
Cost of x meters ropes = Rs. d
∴ Cost of 1 meters ropes = Rs. d /x
∴ Cost of y meters ropes = Rs. dy/x
- A tree is 12 m tall and casts an an 8 m long shadow. At the same time, a flag pole caste a 100 m long shadow. How long is the flag pole ?
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∵ 8 m shadow means original height = 12 m
∴ 1 m shadow means original height = 12/8 mCorrect Option: A
∵ 8 m shadow means original height = 12 m
∴ 1 m shadow means original height = 12/8 m
∴ 100 m shadow means original height = (12/8) x 100 m
= (6/4) x 100 = 6 x 25 = 150 m
- In a race , Ravi covers 5 km in 20 min. How much distance will he cover in 100 min ?
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∵ Distance covered in 20 min = 5 km
∴ Distance covered in 1 min = 5/20 kmCorrect Option: D
∵ Distance covered in 20 min = 5 km
∴ Distance covered in 1 min = 5/20 km
∴ Distance covered in 100 min = (5/20) x 100
= 5 x 5 = 25 km
- If 45 m of a uniform rod weight 171 kg, then what will be the weight of 12 m of the same rod ?
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Let the required weight be w kg.
Less length, Less weight (Direct proportion)
45 : 12 :: 171 : wCorrect Option: D
Let the required weight be w kg.
Less length, Less weight (Direct proportion)
45 : 12 :: 171 : w
∴ w = (12 x 171)/45 = 45.6 kg