Square root and cube root
- 250 / √? = 10
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Let 250 / √x = 10.
Then, √x= 250 / 10 = 25Correct Option: A
Let 250 / √x = 10.
Then √x= 250 / 10 = 25
∴ x = 625
- Find the cube root of 19683.
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In 19683, 19 lies between 23 and 33, so left digit is 2 and 683 ends with 3, so right digit is 7.
Correct Option: D
In 19683, 19 lies between 23 and 33, so left digit is 2 and 683 ends with 3, so right digit is 7.
thus 27 is a cube root of 19683.
- √4/3 - √3/4 = ?
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√4/√3 - √3/√4
= 2/√3 - √3/2
= (4 - 3)/2√3
= 1/2√3Correct Option: A
√4/√3 - √3/√4
= 2/√3 - √3/2
= (4 - 3)/2√3
= 1/2√3
- If √2 = 1.4142, then the approximate value of 1/√2/9 is ?
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√2/9
= √2/√9
= √2/3
= 1.4142/3Correct Option: B
√2/9
= √2/√9
= √2/3
= 1.4142/3
∴ 1/√2/9 = 0.4714
- If √3 = 1.732, then the approximate value of 1/√3 is ?
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1/√3 = 1/√3 x (√3 / √3)
= √3/3
= 1.732 / 3Correct Option: C
1/√3 = 1/√3 x (√3 / √3)
= √3/3
= 1.732 / 3
= 0.577