Plane Geometry

Plane Geometry

Easy Questions
Moderate Questions
Difficult Questions
Plane Geometry Tutorial

Aptitude

Simplification
Number System
Fractions
Elementary Algebra
LCM and HCF
Approximation
Unitary Method
Linear Equation
Quadratic Equation
Discount
Average
Surds and Indices
Percentage
Square root and cube root
Order of Magnitude
Work and Wages
Odd Man Out and Series
Algebra
Profit and Loss
Stocks and Shares
True Discount
Ratio, Proportion
Partnership
Alligation or Mixture
Time and Work
Pipes and Cistern
Speed, Time and Distance
Problem on Trains
Height and Distance
Banker's Discount
Boats and Streams
Races and games
Problems on Ages
Clocks and Calendars
Simple interest
Compound Interest
Sets and Functions
Area and Perimeter
Volume and Surface Area of Solid Figures
Sequences and Series
Plane Geometry
Logarithm
Probability
Permutation and Combination
Statistics
Mensuration
Trigonometry
Aptitude miscellaneous
  1. In a ∆ABC, if 2 ∠ A = 3 ∠ B = 6∠C, value of ∠ B is








  1. View Hint View Answer Discuss in Forum

    As per the given in question,
    ∴ 2∠A = 3∠B = 6∠C

    ⇒
    2∠A
    		 =
    3∠B
    		 =
    6∠C
    666

    ⇒
    ∠A
    		 =
    ∠B
    		 =
    ∠C
    321

    ⇒ ∠A : ∠B : ∠C = 3 : 2 : 1
    ∴ ∠B =
    2
    		× 180°
    1 + 2 + 3

    Correct Option: A

    As per the given in question,
    ∴ 2∠A = 3∠B = 6∠C

    ⇒
    2∠A
    		 =
    3∠B
    		 =
    6∠C
    666

    ⇒
    ∠A
    		 =
    ∠B
    		 =
    ∠C
    321

    ⇒ ∠A : ∠B : ∠C = 3 : 2 : 1
    ∴ ∠B =
    2
    		× 180°
    1 + 2 + 3

    ∠B =
    2
    		× 180° = 60°
    6

  1. In a ∆ABC, ∠A + ∠B = 70° and ∠B + ∠C = 130°, value of ∠A is








  1. View Hint View Answer Discuss in Forum

    In ∆ ABC,
    As we know that , ∠A + ∠B + ∠C = 180°
    Given , ∠A + ∠B = 70° and ∠B + ∠C = 130°

    Correct Option: B

    In ∆ ABC,
    As we know that , ∠A + ∠B + ∠C = 180°
    Given , ∠A + ∠B = 70° and ∠B + ∠C = 130°
    ∴ ∠A = (∠A + ∠B + ∠C) – (∠B + ∠C)
    ∠A = 180– 130°= 50°

  1. Angle between sss ∠B is








  1. View Hint View Answer Discuss in Forum

    As per the given in question , we draw a figure of triangle ABC

    ∠BPC = 120°
    ∴ ∠PBC + ∠PCB = 180°– 120°= 60°

    Correct Option: D

    As per the given in question , we draw a figure of triangle ABC

    ∠BPC = 120°
    ∴ ∠PBC + ∠PCB = 180°– 120°= 60°
    ∴ ∠ABC + ∠ACB = 2 × 60° = 120°
    ∴ ∠A = 180 – 120 = 60°

  1. For a triangle ABC, D, E, F are the mid-points of its sides. If ∆ABC = 24 sq. units then ∆DEF is








  1. View Hint View Answer Discuss in Forum

    On the basis of given in question , we draw a figure triangle ABC ,

    Here , ∆ABC = 24 sq. units
    From figure , we have

    ∆DEF =
    1
    		 ∆ ABC
    4

    Correct Option: B

    On the basis of given in question , we draw a figure triangle ABC ,

    Here , ∆ABC = 24 sq. units
    From figure , we have

    ∆DEF =
    1
    		 ∆ ABC
    4

    ∆DEF =
    1
    		 × 24 = 6 Sq. unit
    4

  1. If I be the incentre of ∆ ABC and ∠B = 70° and ∠C = 50°, then the magnitude of ∠BIC is








  1. View Hint View Answer Discuss in Forum

    Firstly , We draw a figure of triangle ABC whose I is incentre ,

    Here , ∠B = 70° and ∠C = 50°

    ∠IBC =
    70°
    		 = 35° ;
    2

    ∠ICB =
    50°
    		 = 25° ;
    2

    Correct Option: C

    Firstly , We draw a figure of triangle ABC whose I is incentre ,

    Here , ∠B = 70° and ∠C = 50°

    ∠IBC =
    70°
    		 = 35° ;
    2

    ∠ICB =
    50°
    		 = 25° ;
    2

    We know that , ∠BIC + ∠ICB + ∠IBC = 180°
    ∴ ∠BIC = 180° – 35° – 25°
    ∠BIC = 180° – 60° = 120°