Average
- The batting average of a cricket player for 64 innings is 62 runs. His highest score exceeds his lowest score by 180 runs. Excluding these two innings, the average of remaining innings becomes 60 runs. His highest score was
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Let the cricketer’s highest score be n runs.
The batting average of a cricket player for 64 innings = 62 runs
According to question ,
∴ 60 × 62 + n +n – 180 = 64 × 62
⇒ 3720 + 2n – 180 = 3968Correct Option: D
Let the cricketer’s highest score be n runs.
The batting average of a cricket player for 64 innings = 62 runs
According to question ,
∴ 60 × 62 + n +n – 180 = 64 × 62
⇒ 3720 + 2n – 180 = 3968
⇒ 2n = 428
⇒ n = 214 runs
- A cricket batsman had a certain average of runs for his 11 innings. In the 12th innings, he made a score of 90 runs and thereby his average of runs was decreased by 5. His average of runs after 12th innings is :
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Let the batsman’s average in 11 innings be n runs.
According to question,∴ 11n + 90 = n - 5 12
Correct Option: C
Let the batsman’s average in 11 innings be n runs.
According to question,∴ 11n + 90 = n - 5 12
⇒ 11n + 90 = 12n – 60
⇒ n = 150
∴ Required average = 150 – 5 = 145
- The average of runs scored by a player in 10 innings is 50. How many runs should he score in the 11th innings so that his average is increased by 2 runs?
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Given , The average of runs scored by a player in 10 innings = 50
Let the number of runs scored in 11th innings be n.
According to question ,
∴ 10 × 50 + n = 11 × 52
⇒ 500 + n = 572
⇒ n = 572 – 500 = 72 runs
Second method to solve this question with the help of given formula :
Here, T = 50, N = (10 + 1) = 11, t = 2Correct Option: B
Given , The average of runs scored by a player in 10 innings = 50
Let the number of runs scored in 11th innings be n.
According to question ,
∴ 10 × 50 + n = 11 × 52
⇒ 500 + n = 572
⇒ n = 572 – 500 = 72 runs
Second method to solve this question with the help of given formula :
Here, T = 50, N = (10 + 1) = 11, t = 2
Required Runs = T + Nt
Required Runs = 50 + 11 × 2 = 72
- A cricketer has a certain average of runs for his 8 innings. In the ninth innings, he scores 100 runs, thereby increases his average by 9 runs. His new average of runs is
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Let the average of runs of the cricketer in 8 innings be p .
According to the question,8p + 100 = p + 9 9
⇒ 8p + 100 = 9p + 81
Correct Option: C
Let the average of runs of the cricketer in 8 innings be p .
According to the question,8p + 100 = p + 9 9
⇒ 8p + 100 = 9p + 81
⇒ p = 100 – 81 = 19
∴ New average of runs = 19 + 9 = 28
- A cricketer had a certain average of runs for his 64 innings. In his 65th innings, he is bowled out for no score on his part. This brings down his average by 2 runs. His new average of runs is
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Let the cricketer’s average of runs for his 64 innings be p runs.
&there45; Total number of runs in 64 innings = 64pAccording to the question, 64p + 0 = p - 2 65
⇒ 64p = 65p – 130
⇒ p = 130
Correct Option: B
Let the cricketer’s average of runs for his 64 innings be p runs.
&there45; Total number of runs in 64 innings = 64pAccording to the question, 64p + 0 = p - 2 65
⇒ 64p = 65p – 130
⇒ p = 130
∴ New average of runs = p – 2 = 130 – 2 = 128
