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If a two-stage amplifier is required to have an upper cut-off frequency of 2 MHz and a lower cut-off frequency of 30 Hz then upper and lower cut -off frequencies of individual st age are respectively
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- 4 MHz, 60 Hz
- 3 MHz, 20 Hz
- 3 MHz, 60 Hz
- 4 MHz, 20 Hz
Correct Option: B
| fL* = | ||
| √21 / n - 1 |
and fH* = fH √21 / n - 1
Putting n = 2, we have
fH ≈ 3.1 MHz and fL ≈ 19.3 MHz ≈ 20 Hz
