Assuming operational amplifier to be ideal, gain Vout /

Assuming operational amplifier to be ideal, gain V_out / V_in for the circuit shown in the given figure is

Using KCL at the node 1 we have

	V - 0	+	V	+	V - V_out	= 0
	10		1		10

⇒ 12V = V_out ...(i)
Also, using KCL at inverting node, we get

	V_in - 0	=	0 – V
	1		10

⇒ V = – V_in. 10 ...(ii)
From equations (i) and (ii), we get

	V_out	= -120
	V_in