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A Bode magnitude plot for the transfer function G(s) of a plant is shown in the figure. Which one of the following transfer functions best describes the plant?
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1000(s + 10) s + 1000
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10(s + 10) s(s + 1000) -
s + 1000 10s (s + 10) -
s + 1000 10 (s + 10)
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Correct Option: D
Initial slope is zero
It is type ‘0’ system
(No pole at origin)
Starting gain = 20 log K db
20 log K = 20 K = 10
Given T/F
| G(s) = | ||
| 10 (s + 10) |
| = | 1000 |  | 1 + |  | |
| 1000 | |||||
| 10 × 10 | | 1 + | | ||
| 10 | |||||
| G(s) = | 10 | | 1 + | | |
| 1000 | |||||
| 1 + | | |||
| 10 | |||||
