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The system shown in the figure given below is
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- stable
- unstable
- conditionally stable
- stable for input u1, but unstable for input u2
Correct Option: D
Transfer function for u1
TF1 = | = | ||||||||||||
1 + | ![]() | ![]() | . | ![]() | ![]() | (s + 3) | |||||||
s + 2 | s - 1 |

TF2(s) = | ![]() | ![]() | |||||
s - 1 | |||||||
1 + | ![]() | ![]() | . | ![]() | ![]() | ||
s - 1 | s + 2 |
= | ||
(s + 3)(s - 1) |
Hence unstable, as it has pole at right side of s-plane.