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In the given circuit, if the power dissipated in the 6 Ω resistor is zero then V is
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- 20 √2 ∠ 45°
- 20 ∠ 30°
- 20 ∠ 45°
- 20 √2 ∠ 30°
- 20 √2 ∠ 45°
Correct Option: A
From the circuit, 20 ∠ 0° = I1 (1 + j)
| ⇒ I1 = | ||
| 1 + j |
| and, 20 ∠ 0° = I1 + 5I2 = | + 5I2 | |
| 1 + j |
| ⇒ 5I2 = | ||
| 1 + j |
| Then , V = 10I2 = 2 . | = | |||
| 1 + j | 1 + j |
= 20 √2 ∠ 45°
