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After closing the switch ‘S’ at t = 0, the current i(t) at any instant ‘t’ in the network shown in the given figure will be

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- 10 + 10 e100 t
- 10 – 10 e100 t
- 10 + 10 e–100 t
- 10 – 10 e–100 t
Correct Option: D
It can be verified by checking the value of the current at t = 0 and at t = ∞ which
| should be zero and | = 10 A respectively . | |
| 1 |