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The efficiency of a 100 kVA transform is 0.98 at full as well as at half load. For this transformer at full load the copper loss is
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- less than core loss
- equal to core loss
- more than core loss
- none of these
Correct Option: C
For 100 kV transformer, we have
At full load (η = 0.98),
| 0.98 = | |
| 100 + Wcu + Wco |
| ⇒ Wcu + Wco + 100 = | |
| 0.98 |
⇒ Wcu + Wco = 2.04 ...(i)
At half load,
| 0.98 = | |
| 50 + Wcu/4 + Wco |
| ⇒ | + Wco = | − 50 | ||
| 4 | 0.98 |
| ⇒ | + Wco = 1.02 ...(ii) | |
| 4 |
From equations (i) and (ii), we get
| = 1.02 | |
| 4 |
⇒ Wcu = 1.36 kW
Wcore = 0.68 kW
Hence at full load copper loss is more than core loss.