Home » Surveying » Surveying miscellaneous » Question

Surveying miscellaneous

  1. The local mean time at a place located in longitude 90° 40' E when the standard time is 6 hours and 30 minutes and the standard meridian is 82° 30' E is
    1. 5 hours, 2 minutes and 40 seconds
    2. 5 hours, 57 minutes and 20 seconds
    3. 6 hours, and 30 minutes
    4. 7 hours, 02 minutes and 40 seconds
Correct Option: D

Difference between standard meridian and longitude of place = 90° 40' E – 82° 30'. = 8° 10'.
1° means 4 minutes


∴ 8° 10' means
49
°
6

∴ Time =
49°
× 4 = 32 min 40 seconds
6

∴ Total time = 6 hours + 30 min + 32 min 40 sec = 7h 2 m 40s.



Your comments will be displayed only after manual approval.