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A hydraulic jump takes place in a triangular channel of vertex angle 90°, as shown in figure. The discharge is 1m3 /s and the pre-jump depth is 0.5m. What will be the post-jump? (Take g = 9.81 m/s2)
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- 0.57 m
- 0.91 m
- 1.02 m
- 1.57 m
Correct Option: C
Taking specific force at 2 sections:
| z = | ||
| 3 |
| ⇒ | + |  | y12 × |  | = | + | | y22 × | | ||||
| 9.81 × y12 | 3 | 9.81 × y12 | 3 |
y1 = 0.5 m
| ⇒ 0.449 = | + | |||
| 9.81y23 | 3 |
⇒ y2 = 1.02 m
