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Find the value of √(x² + y² + z)(x + y - 3z) ÷ ³√xy³z² when x = + 1, y = –3, z = – 1.
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- 1
- 0
- –1
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1 2
- 1
Correct Option: C
| Expression = | = 1 | ||
| ³√xy³z² |
Putting x = 1, y = –3, z = –1
| Expression = | = 1 | ||
| ³√ 1 × (-27) × 1 |
| Expression = | = -1 | |
| -3 |
Note : Original question is :
√(x² + y² + z)(x + y - 3z) ÷ ³√xy³z²
which gives answer = – √7 which is not in options.
