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If x = a (b – c), y = b (c – a), z = c (a – b), then the value of 
x 
3 + y 3 + z 3 is : a b c
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2xyz abc
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xyz abc
- 0
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3xyz abc
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Correct Option: D
x = a (b – c)
| ⇒ | = b – c | |
| a |
Similarly, y = b (c – a)
| ⇒ | = c – a | |
| b |
| and | = a – b | |
| c |
| ∴ | + | + | = b – c + c – a + a – b = 0 | |||
| a | b | c |
| ∴ | | | 3 | + | | | 3 | + | | | 3 | = 3 × | × | × | = | ||||||||
| a | b | c | a | b | c | abc |
[If a + b + c = 0, a3 + b3 + c3 = 3 abc]
