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A horizontal jet of water with its cross-sectional area of 0.0028 m² hits a fixed vertical plate with a velocity of 5 m/s. After impact the jet splits symmetrically in a plane parallel to the plane of the plate. The force of impact (in N) of the jet on the plate is
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- 90
- 80
- 70
- 60
Correct Option: C
Force on plate = (ra av)v
= ra .aV²
= 1000 × 0.0028 × 5²
= 70 N