The following data are given for the laboratory sample.

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The following data are given for the laboratory sample. σ_o' = 175 kPa; e_o = 1.1; σ_o' + ∆σ_o' = 300 kPa; e = 0.9 If thickness of the clay specimen is 25 mm, the value of coefficient of volume comprehensibility is __________ × 10^–4 m² /kN.

1. 7.3 m
2. 4.6 m
3. 5.8 m
4. 6.3 m

Correct Option: D

7.6 to 8

M_v =	a_v	=	∆e / ∆σ
	1 + e₀		1 + e₀

=	(1.1 - 0.9)
	125 × 2.1

= 7.61 × 10^–6 m² /kN
H = 6.3 m