Then, p and q are

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Direction: The complete solution of the ordinary differential equation

	d²y	+ p	dy	+ qy = 0 is
	dx²		dx

y = c₁e^-x + c²e^-3x

Then, p and q are

1. p = 3, q = 3
2. p = 3, q = 4
3. p = 4, q = 3
4. p = 4, q = 4

Correct Option: C

	d²y	+ p	dy	+ qy = 0
	dx²		dx

D² + pD + q = 0
It's solutions is y = c₁e^-x + c₂e^-3x
⇒ m = –1, n = –3
If m and n are two roots of the above equation, then
m + n = –p,
⇒ –1 – 3 = –p,
⇒ p = 4
and mn = q,
⇒ (–1) (–3) = q,
⇒ q = 3