Direction: The circular disc shown in its pian view in the figure rotates in a plane parallel to the horizontal plane about the point O at a uniform angular velocity ω . Two other points A and B are located on the line OZ at distances rA and rB from O respectively.
-
The velocity of point B with respect to point A is a vector of magnitude
-
- 0
- ω(rB – rA) and direction opposite to the direction of motion of point B
- ω(rB – rA) and direction same as the direction of motion of point B.
- ω²(rB – rA) and direction being from O to Z
- 0
Correct Option: C
B has the linear velocity ωB rB
A has the linear velocity ωA rA
Obviously, ωB rB > ωA rA
because ωA = ωB = ω and rB > rA
∴ ωrB > ωrA
So relative velocity = ω(rB – rA) in the direction of motion of point B.
and, it will experience a centripetal acceleration of ω² (rB – rA) towards “O”
