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A rigid link PQ is 2 m long and oriented at 20° to the horizontal as shown in the figure. The magnitude and direction of velocity VQ, and the direction of velocity VP are given. The magnitude of VP (in m/s) at this instant is

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- 2.14
- 1.89
- 1.21
- 0.96
- 2.14
Correct Option: D
By Instantaneous center method;say ω = angular velocity of rod
vq = rq . ω ...(i)
vp = rp . ω ...(ii) Dividing equation (i) with equation (ii) we get
| = | ; vp = | .vq | ||||
| vp | rp | rq |
| Now by sine law, | = | |||
| sin(45° + 20°) | sin(70°) |
| = | ||||
| rq | sin(70°) |
| So , vp = | vq = 0.96 | |
| sin(70°) |