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As shown in figure, a mass of 100 kg is held between two springs. The natural frequency of vibration of the system in cycle/s, is
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1 2π
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5 π
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10 π
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20 π
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Correct Option: C
S = S1 + S2 = 20 + 20 = 40 kN/m = 40,000 N/m
∴ Natural frequency of vibration of the system,
| fn = | √S / m | |
| 2π |
| fn = | √(400 × 1000)/ 100 | = | ||
| 2π | 2π |
| fn = | ||
| π |
