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The population of a town at the beginning of the year 1986 was 2,65,000. If the rate of increase be 52 per thousand of the population. Find the population at the beginning of the year 1991. ?
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- 3,40,400
- 3,41,400
- 3,42,400
- 3,43,400
Correct Option: B
We have r = Rate of increase
= 52/1000 x 100
= 5.2, n = 5, P0 = 265000
∵ P = 265000(1 + 5.2 / 100)5
⇒ log P = log 265000 + 5(log 105.2 - log 100)
= 5.4232 + 5(2.0220 - 2)
= 5.4232 + 0.1100
= 5.5332
∴ P = antilog(5.5332) = 341400
