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The maximum and minimum shear stresses in a hollow circular shaft of outer diameter 20 mm and thickness 2 mm, subjected to a torque of 92.7 Nm will be
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- 59 MPa and 47.2 MPa
- 100 MPa and 80 MPa
- 118 MPa and 160 MPa
- 200 MPa and 160 MPa
Correct Option: B
= | ||||
r | J |

τmax = | J |
= | (π/32) × (204 - 104) |
≈ 100 N/mm2
τmax is at r = 16/2 = 8 mm
τmax = (100/10) × rmin = 80 N/mm2 = 80 mPa