Divergence of the vector field x2zî + xyĵ -

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Divergence of the vector field
x²zî + xyĵ - yz²k̂ at (1, -1, 1) is

1. 0
2. 3
3. 5
4. 6

Correct Option: C

Given F = x² aî + xyĵ - yz²k̂
div F = ∇ . F

=	δ	(x²z) +	δ	(xy) +	δ	(-yz²)
	δx		δy		δz

div F at (1, – 1, 1) = 2 + 1 + 2 = 5