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The value of the integral ^∞∫_-∞ dx is
1 + x²

1. – π
2. – π/2
3. π/2
4. π

Correct Option: D

I = ^∞∫_-∞	dx
	1 + x²

= [tan^-1 x]^∞_-∞ = tan^-1(∞) - tan^-1(-∞)

=	π	-		-	π		= π
	2				2