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Engineering Mathematics Miscellaneous

Engineering Mathematics

  1. The value of the integral 2∫0x∫0dydx
    1. 1
      (e - 1)
      2
    2. 1
      (e² - 1)²
      2
    3. 1
      (e² - e)
      2
    4. 1
      e -
      1
      ²
      2e
Correct Option: B

2∫0x∫0ee+ydy dx = 2∫0ex(x∫0eydy)dx
= 2∫0ex(ey)0x dx = 2∫0(ex - 1)dx

= 2∫0(e2x - ex) dx =
e2x
- ex²
20

=
e4
- e²
1
+ 1 =
e4
- e²
1
2222

=
1
(e4 - 2e² + 1) =
1
(e² - 1)²
22



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