The integral when evaluated by using Simpson's 1/3 rule

The integral when evaluated by using Simpson's 1/3 rule on two equal subintervals each of length 1, equals

Given : ∫³₁	1	dx
	x

Here, a = 1, b = 3, n = 2

h =	b -a	= 1
	n

By Simpson's rule

∫³₁	1	dx =	1	h[ y₁ + y₃) + 4(y₂)]
	x		3

=	1	(1) [(1 + 0.33) + 4 (0.51)] = 1.11
	3