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Theory of Machines Miscellaneous

  1. For the epicyclic gear arrangement shown in the figure, ω2 = 100 rad/s clockwise (cw) and ωarm = 80 rad/s counter clockwise (ccw). The angular velocity ω5 (in rad/s) is
    1. 0
    2. 70 cw
    3. 140 ccw
    4. 140 cw
Correct Option: B


Given: ωarm = – 80 rad/sec = Y (CCW)
ω2 = 100 rad/sec = X + Y (CW)
∴ X = 100 – Y = 100 + 8 = 108 rad/sec (CW)

Also, ωs = -
1
X + Y = -
1
(180) + (-80)
33

= – 140 rad/sec (CCW)
∴ ωs = 140 rad/sec (CW)
Note: CCW → Counter Clock Wise
CW → Clock Wise



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