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For the epicyclic gear arrangement shown in the figure, ω2 = 100 rad/s clockwise (cw) and ωarm = 80 rad/s counter clockwise (ccw). The angular velocity ω5 (in rad/s) is
-
- 0
- 70 cw
- 140 ccw
- 140 cw
Correct Option: B
Given: ωarm = – 80 rad/sec = Y (CCW)
ω2 = 100 rad/sec = X + Y (CW)
∴ X = 100 – Y = 100 + 8 = 108 rad/sec (CW)
Also, ωs = - | X + Y = - | (180) + (-80) | ||
3 | 3 |
= – 140 rad/sec (CCW)
∴ ωs = 140 rad/sec (CW)
Note: CCW → Counter Clock Wise
CW → Clock Wise