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A disk clutch is required to transmit 5 kW at 2000 rpm. The disk has a friction lining with coefficient of friction equal to 0.25. Bore radius of friction lining is equal to 25 mm. Assume uniform contact pressure of 1 MPa. The value of outside radius of the friction lining is
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- 39.4 mm
- 49.5 mm
- 97.9 mm
- 142.9 mm
Correct Option: A
| Torque, T = | = 23.87 Nm | |
| 2π × N |
= Axial thrust,
W = P × π (r²1 × r²2)
| But T = | μ × P × π(r²1 × r²2) | |
| 3 |
| = μwr | |
| (r²1 × r²2) |
∴ r2 = 39.4 mm
