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Starting from x0 = 1, one step of NewtonRaphson method in solving the equation x3 + 3x – 7 = 0 gives the next value (x1) as
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- x1 = 0.5
- x1 = 1.406
- x1 = 1.5
- x1 = 2
Correct Option: C
| By N-R method, xn+1 = xn - | , x0 = 1 | f'(x) |
f(x) = x3 + 3x - 7
⇒ f(1) = -3,
| ⇒ x1 = x0 - | f'(x0) |
⇒ f(x) = 3x² + 3,
⇒ f(1) = 6,
| x4 = 1 - | = 1 - (-0.5) =1.5 | 6 |
