The number of degrees of freedom of a planar linkage with

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The number of degrees of freedom of a planar linkage with 8 links and 9 simple revolute joints is

1. 1
2. 2
3. 3
4. 4

Correct Option: C

Number of degree of freedom,
n =3(l – 1) – 2j – h
= (3 × 7) – (2 × 9) – 0 = 3