The number of degrees of freedom of the linkage shown in

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The number of degrees of freedom of the linkage shown in the figure is

1. - 3
2. 0
3. 1
4. 2

Correct Option: C

Number of links, N = 6
Total number as binary joints, j = 7
F = 3 (N – 1) – 2j = 15 – 14 = 1.