-
A man travelled a certain distance by train at the rate of 25 kmph. and walked back at the
rate of 4 kmph. If the whole journey took 5 hours 48 minutes, the distance was
-
- 25 km
- 30 km
- 20 km
- 15 km
Correct Option: C
Let the distance be x km.
Total time = 5 hours 48 minutes
| = 5 + | = | ![]() | 5 + | ![]() | hours | ||
| 60 | 5 |
| = | hours | |
| 5 |
| ∴ | + | = | |||
| 25 | 4 | 5 |
| ⇒ | = | ||
| 100 | 5 |
⇒ 5 × 29x = 29 × 100
| ⇒ x = | = 20 km. | |
| 5 × 29 |
Second Method :
Here, x = 25, y = 4
| Average speed = | |
| x + y |
| = | = | ||
| 25 + 4 | 29 |
| Total Distance = | × 5 | ||
| 29 | 5 |
| = | × | = 40 km | ||
| 29 | 5 |

