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Two trains start from station A and B and travel towards each other at speed of 16 miles/ hour and 21 miles/ hour respectively. At the time of their meeting, the second train has travelled 60 miles more than the first. The distance between A and B (in miles) is :
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- 444
- 496
- 333
- 540
Correct Option: A
Let the trains meet after t hours
Then, 21t – 16t = 60
⇒ 5t = 60 ⇒ t = 12 hours
∴ Distance between A and B
= (16 + 21) × 12
= 37 × 12 = 444 miles
Second Method :
Here, a = 21, b = 16, d = 60
| Distance between A and B = |  |  | × d | |
| a − b |
| = | | | × 60 | |
| 21 − 16 |
| = | × 60 | |
| 5 |
= 37 × 12 = 444 miles
