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Two places P and Q are 162 km apart. A train leaves P for Q and simultaneously another train leaves Q for P. They meet at the end of 6 hours. If the former train travels 8 km/hour faster than the other, then speed of train from Q is
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12 5 km/hour 6 -
10 5 km/hour 6 -
9 1 km/hour 2 -
8 1 km/hour 2
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Correct Option: C
Speed of train starting from Q = x kmph
∴ Speed of train starting from P = (x + 8) kmph
According to the question,
PR + RQ = PQ
⇒ (x + 8) × 6 + x × 6 = 162
[Distance = Speed × Time]
⇒ 6x + 48 + 6x = 162
⇒ 12x = 162 – 48 = 114
⇒ x = | = | ||
12 | 2 |
= 9 | kmph | |
2 |