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is 25 minutes late. His usual time to cover this distance isWalking at 6 th of his usual speed a man 7
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- 2 hours 30 minutes
- 2 hours 15 minutes
- 2 hours 25 minutes
- 2 hours 10 minutes
Correct Option: A
Time and speed are inversely proportional.
∴ | × Usual time – Usual time = 25 minutes | |
6 |
⇒ | − 1 | = 25 minutes | |||
6 |
⇒ Usual time × | = 25 minutes | |
6 |
∴ Usual time = 25 × 6
= 150 minutes
= 2 hours 30 minutes
Second Method :
Here, A = 6, B = 7,
t = | = | hrs. | ||
60 | 12 |
Usual time = | × time | |
Diff. of A and B |
= | × | = | hrs. | |||
(7 − 6) | 12 | 2 |
= 2 hours 30 minutes