A train covers a distance of 3584 km in 2 days 8 hours.

A train covers a distance of 3584 km in 2 days 8 hours. If it covers 1440 km on the first day and 1608 km on the second day, by how much does the average speed of the train for the remaining part of the journey differ from that for the entire journey ?

Remaining distance
= (3584 – 1440 – 1608) km
= 536 km.

This distance is covered at the rate of	536	= 67 kmph.
	8

Average speed of whole journey

=	3584	= 64 kmph
	56

∴ Required difference in speed
= (67 – 64) kmph i.e. = 3 kmph
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