A thief steals a car at 1.30 p.m. and drives it off at 40

A thief steals a car at 1.30 p.m. and drives it off at 40 km/hr. The theft is discovered at 2 p.m. and the owner sets off in another car at 50 km/hr. He will overtake the thief at

Distance covered by the thief in half an hour

=	1	× 40 = 20 km
	2

Relative speed of car owner
= 50 – 40 = 10 km

∴ Required time =	Difference of distance
	Relative speed

=	20	= 2 hours
	10

i.e. at 4 p.m.