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A thief is stopped by a policeman from a distance of 400 metres. When the policeman starts the chase, the thief also starts running. Assuming the speed of the thief as 5 km/h and that of policeman as 9 km/h, how far the thief would have run, before he is over taken by the policeman ?
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- 400 metre
- 600 metre
- 500 metre
- 300 metre
Correct Option: C
Distance between thief and policeman = 400 metre
Relative speed of policeman with respect to thief
= (9 – 5) kmph
= 4 kmph
| = | ![]() | ![]() | m./sec. | |
| 18 |
| = | m./sec. | |
| 9 |
Time taken in overtaking the thief
| = | ![]() | ![]() | second | |
| 10/9 |
| = | ![]() | ![]() | second | |
| 10 |
= 360 second
∴ Distance covered by thief
= Speed × Time
| = | ![]() | 5 × | × 360 | ![]() | metre | |
| 18 |
= 500 metre

