Shri X goes to his office by scooter at a speed of 30km/h

Shri X goes to his office by scooter at a speed of 30km/h and reaches 6 minutes earlier. If he goes at a speed of 24 km/h, he reaches 5 minutes late. The distance of his office is

Let the distance of office be x km.

∴	x	−	x	=	11
	24		30		60

⇒	5x − 4x	=	11
	120		60

⇒	x	=	11
	120		60

⇒ x =	11	× 120 = 22 km.
	60

Second Methdod :
Here, S₁ = 24, t₁ = 5
S₂ = 30, t₂ = 6

Distance =	(S₁ ×S₂)(t₁ + t₂)
	S₂ −S₁

=	24 × 30(5 + 6)
	30 − 24

=	720 × 11	= 22 km
	6 × 60